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• Time of issue:2012-12-02
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(Summary description)LOUDA chiller wiring current standard

Estimate tips:

Multiply it by two five and nine, and go up one minus.

Thirty-five times three-fifth, both groups are reduced by five.

Conditions are subject to change and discount, and copper at high temperature of 10% is upgraded.

The number of pipes through the pipe is two-four-four, eighty-six percent full load.

Explanation:

(1) In this section, the current carrying capacity (safety current) of various insulated wires (rubber and plastic insulated wires) is not directly pointed out, but is expressed by "section multiplied by a certain multiple" and obtained through mental arithmetic. It can be seen from Table 53 that the multiple decreases as the cross section increases. "Multiply by 2.5 and multiply by nine, and go up by one." It is said that the aluminum core insulated wires with various cross sections of 2.5 mm 'and below have a current carrying capacity of about 9 times the number of cross sections. For example, a 2.5mm 'wire has a current carrying capacity of 2.5 × 9 = 22.5 (A). The multiple relationship between the current carrying capacity and the cross section of the conductor from 4mm 'and above is arranged upward along the line number, and the multiple is decreased by 1, namely 4 × 8, 6 × 7, 10 × 6, 16 × 5, 25 × 4.

"Thirty-five times three point five, both points are reduced by five points," said 35mm "The current carrying capacity of the wire is 3.5 times the number of sections, that is, 35 × 3.5 = 122.5 (A). From For conductors of 50mm 'and above, the multiple relationship between the current carrying capacity and the number of sections becomes two sets of two wire numbers, and the multiple is reduced by 0.5 in sequence. That is, the current carrying capacity of 50 and 70mm' conductors is 3 Times; the current carrying capacity of the 95, 120mm "wire is 2.5 times its cross-sectional area, and so on. "Conditions are subject to change and discounts, and high-temperature 10% copper upgrades." The above formula is determined by the aluminum core insulated wire, exposed to the environment temperature of 25 ℃. If the aluminum core insulated wire is applied in an area where the ambient temperature is higher than 25 ℃ for a long time, the current carrying capacity of the conductor can be calculated according to the above-mentioned calculation method, and then a 10% discount can be used; Its ampacity is slightly larger than that of the aluminum wire of the same specification. According to the above formula, the ampacity of the aluminum wire is increased by one line number. For example, the current carrying capacity of 16mm ’copper wire can be calculated as 25mm2 aluminum wire.

If it is a copper core wire:

1.5 squares can carry a maximum of 12A-13.5A

2.5 squares can carry a maximum of 16A-18A

4 squares can carry a maximum of 32A-36A

6 square up to 48A-54A

If it is an aluminum core wire:

1.5 squares can carry 6A-6.75A

2.5 squares can carry a maximum of 8A-9A

4 square up to 16A-18A

6 square up to 24A-27A

These values ​​are not accurate, the specific values ​​are related to temperature!

National standard allowed long-term current:

4 square is 25-32A

6 square is 32-40A

The ampacity under the working temperature of 30 ℃ and long-term continuous 90% load is as follows:

1.5 mm2-18A

2.5 mm2-26A

4 mm2-26A

6 mm2-47A

10 mm2-66A

16 mm2-92A

25 mm2-120A

35 mm2-150A

Power P = voltage U × current I = 220 volts × 18 amps = 3960 watts

Wire load current value (part) as specified in GB4706.1-1992 / 1998

Copper core wire: Copper core wire cross-section area: Allowable long-term current: 2.5 mm2 (16A ～ 25A) ..

4 square millimeters (25A ～ 32A) .. 6 square millimeters (32A ～ 40A)

Aluminum core wire: Aluminum core wire cross-section area: Allow long-term current: 2.5 square millimeters (13A ～ 20A)

4mm2 (20A ～ 25A): 6mm2 (25A ～ 32A)

///for example:////

1. Each computer consumes about 200 ~ 300W (about 1 ~ 1.5A), then 10 computers need a 2.5 mm2 copper core wire to supply power, otherwise a fire may occur.



2. The power consumption of three large air conditioners is about 3000W (about 14A), so a single air conditioner needs a separate 2.5 mm2 copper core wire for power supply.

3. The current housing wiring is generally 4 square millimeters of copper wire. Therefore, household appliances that are turned on at the same time must not exceed 25A (that is, 5500 watts). Some people replace the electrical wires in the house with 6 square millimeters of copper wire. Because the wires entering the meter are 4 square millimeters.

4. Early housing (15 years ago) The incoming line is generally 2.5 square millimeters of aluminum wire. Therefore, the household appliances opened at the same time must not exceed 13A (that is, 2800 watts).

5. Household appliances with large power consumption are: air conditioner 5A (1.2HP), electric water heater 10A, microwave oven 4A, rice cooker 4A, dishwasher 8A, washing machine 10A with drying function, electric water heater